molar mass of h3po4
molar mass of H3PO4 IS 97.99g/mol. I don't know what to do with this, I tried: (.005 L)(x M) = (.055 L)(0.258 M) And I got 2.838 mol/L But the answer is wrong apparently. Calculate the formula and molar mass. d. How many H atoms are there in 2.5 mol H3PO4.2.5pt The molar mass of H3PO4 (phosphoric acid) is: 97.993 grams/mol. Molar mass of *2H3PO4 is 195.9904 g/mol Convert between *2H3PO4 weight and moles moles P4O10 = mass / molar mass = 10.00 g / 283.88 g/mol = 0.035226 mol. work out the limiting reagent. moles of H3PO4 = 25.4 g x a million mol/ninety 8 g = 0.259 mol H3PO4 Kg of solvent = (100g - 25.4 g) = seventy 4.6 g = 0.0746 kg Molality = moles of solute/kg of solvent = 0.259 mol/0.0746 kg solvent Molality = 3.47m b. Mass Na3PO4 formed = 0.833 mol X 163.9 g/mol = 137 g Na3PO4 1. c. How many moles of PO43-ions are present in 2.5 moles of phosphoric acid, H3PO4? What am I doing wrong? A 5.00 mL sample of an aqueous solution of H3PO4 requires 55.0 mL of 0.258 M NaOH to convert all of the H3PO4 to Na2HPO4. Solution The molar mass of H3PO4 is 97.99 g. The percent by mass of each of the elements in H3PO4 is calculated as follows: %H=(3(1.008 g) H/ 97.99 g H3PO4)*100%= 3.086% P4O10 + 6H2O ----> 4 H3PO4. Molar Mass: 97.9952. Calculations: Formula: H3PO4 Molar Mass: 97.9937 g/mol 1g=1.02047376515021E-02 mol Percent composition (by mass): Element Count Atom Mass %(by mass) To do this work out how much H3PO4 you would get if all of each reagent individually were to fully react. - 13159451 ams) has entries 4.9, 14.7. H3PO4 is a colorless viscous liquid at room temperature. The one that produces the least H3PO4 is the limiting reagent. Mass H3PO4 consumed = 2.50 mol NaOH X (1 mol H3PO4 / 3 mol NaOH) X 97.99 g/mol = 81.7 g H3PO4 consumed. How many oxygen atoms are in one unit of H3PO4? What is the molar mass of H3PO4? moles H2O = 12.0 g / 18.016 g/mol = 0.66607 mol. H3PO4 is a strong acid and corrosive. Example Reactions: • PH3 + 2 O2 = H3PO4 • 3 KOH + H3PO4 = K3PO4 + 3 H2O • H3PO4 + 5 HCl = PCl5 + 4 H2O • H3PO4 + 3 NH3 = (NH4)3PO4 • H3PO4 + NaOH = NaH2PO4 + H2O Now there is 15 moles of H3PO4 in the initial liter so it is 15M H3PO4! Can someone give me a step by step to the solution? From its MSDS sheet it is 1.680g/mL. Do a quick conversion: 1 grams H3PO4 = 0.010204583427424 mole using the molecular weight calculator and the molar mass of H3PO4. See also our theoretical yield calculator for chemical reactions (probably your next stop to finish the problem set). Mass H3PO4 remaining = 18.3 g H3PO4 remaining. The other product of the reaction is water. Complete the following calculations for H3PO4.4 pts (1pt each) a. mole H3PO4 = 1430 g H3PO4 x 1 mole H3PO4/98 g H3PO4 = 15 moles. Start with a liter of solution which is 1000 mLx 1.680 g/mL gives a mass of 1680 g. mass H3PO4 = 1680 g solution x 85 parts H3PO4/100 parts solution = 1430 g H3PO4. 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